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did I done this correctly and what is the Temperature change, mean. also what ne

ID: 590918 • Letter: D

Question

did I done this correctly and what is the Temperature change, mean. also what need to be at the bottom?

Data Sheet 2 volume of HCI solution, ml molarity of HC1 solution, M number of moles of HC 100 volume of NaOH solution, ml. molarity of NaOH solution, M number of moles of NaOH tnitial temperature of acid,"C 23 initial temperature of base, "C average temperature of reactants, Tps Ca2 final temperature of mixture, T Tinal C 29-23c temperature change, ar, 101x4·1x46 25 35.S0 2S3s.sOJ Q(heat transferred), J number of moles of HCI reacting neutzn k mol-1 mean Hneutzn, kj mol-1 57

Explanation / Answer

All things u have done correctly

Average temperature reactants = 23+24/2 = 23.5 C in both cases

Temperature change = 29 - 23.5 = 5.5 C in both cases

Q heat = mCdT = 100*4.184*5.5 = 2301.2 J in 1st case

Q heat = 102*4.184*5.5 = 2347.2 J in 2nd case

Number of moles of HCl reacting = 0.1 moles in 1st case and 0.102 moles in 2nd case

In 1st case :

delta Hneu = delta H / Moles = 2301.2 / 0.1 = 23.012 KJ/mol

In 2nd case :

delta Hneu = delta H / moles = 2347.2 / 0.102 = 23.012 KJ /mol

Mean = (1st + 2nd) /2 = 1/2 *(23.012 + 23.012) = 23.012 KJ/mol

This is the procedure