a Sapling Learning Substance Consider the decomposition of a metal oxide to its

Question

a Sapling Learning Substance Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M,0,() = 3(s) + 20,8) M304 What is the standard change in Gibbs energy for the reaction, as written, in the forward direction? AG. - 8.600 kJ/mol What is the equilibrium constant of this reaction, as written in the forward direction at 200 K7 74330 x 10 What is the equilibrium pressure of O2(g) over M(s) at 298 K? O Prema ove Up View solution a checa Arwar Ort botes carrers play peltoy terms of use contact useo

Explanation / Answer

Given reaction is: M3O4(s) 3M(s) + 2O2(g) at 296 K

Go(M3O4) = -8.6 kJ/mol

Go(M) = 0

Go(O2) = 0

Gorxn =Goproducts -Goreactants = [Go(M)+ Go(O2)] - Go(M3O4)

Gorxn = [0+0-(-8.6)] kJ/mol = 8.6 kJ/mol = 8600 J/mol

Gorxn = 8600 J/mol

The relation between free energy change and equilibrium constant is given by:

Gorxn = -RTlnKp

8600 J/mol = -(8.314 J/Kmol)x296 K(lnKp)

ln Kp = - (8600 J/mol)/(8.314 J/Kmolx296K) = -3.494

Kp = e-3.494 = 0.0303

Kp= 3.03x 10-2

Equilibrium expression for the reaction is given as:

Kp = (PO2)2

PO2= (3.03x 10-2)1/2

PO2 = 1.74 x10-1

PO2 = 0.174 atm

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