On a lab exam, you have to find the concentrations of the monoprotic (one proton

Question

On a lab exam, you have to find the concentrations of the monoprotic (one proton per molecule) acids HA and HB. You are given 42.5 mL of HA solution in one flask. A second flask contains 45.4 mL of HA, and you add enough HB solution to it to reach a final volume of 50.0 mL. You titrate the first HA solution with 87.3 mL of 0.0906 M NaOH and the mixture of HA and HB in the second flask with 96.4 mL of the NaOH solution. Calculate the molarity of the HA and HB solutions.

_____ M HA
_____ M HB

So far I am 100% sure the concentration is 0.186 M of HA, but I cannot figure out the concentration for HB

Explanation / Answer

Hey, all I can tell you is that these calculations are correct. Your online program is wrong. Sorry. If you have a teacher or online support, I'd hit them up. 0.0906 moles/L * 0.0964L = 0.00873 moles of Base 0.186 moles/L * 0.0454 L = 0.00844 moles of HA 0.00873 moles of base - 0.00844 moles of HA = moles of HB = 0.00029 moles of HB volume of HB = 50-45.4 = 4.6 mL = 0.0046L 0.00029moles/0.0046L = 0.0630 moles/L of HB

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