(a) Consider the combustion of ammonia, given below: 4 NH3(g) + 5 O2(g) 4 NO(g)

Question

(a) Consider the combustion of ammonia, given below:
4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g)
If NH3(g) is decreasing at the rate of 0.450 mol/s, what are the rates of change of O2(g), NO(g), and H2O(g)?



O2(g)/t = mol/s

NO(g)/t = mol/s

H2O(g)/t = mol/s




(b) The decomposition reaction given below:
1 SO2Cl2(g) 1 SO2(g) + 1 Cl2(g)
is carried out in a closed reaction vessel. If the partial pressure of SO2Cl2(g) is decreasing at the rate of 787 torr/min, what is the rate of change of the total pressure in the vessel?



Ptot /t = torr/min

Explanation / Answer

4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) If NH3(g) is decreasing at the rate of 0.450 mol/s rates of change of O2(g)= 5/4 x 0.450 mol/s = 0.5625 NO(g) = 0.450 mol/s H2O(g)= 6/4 x 0.450 mol/s= 0.675 1 SO2Cl2(g) 1 SO2(g) + 1 Cl2(g) SO2Cl2(g) is decreasing at the rate of 787 torr/min rate of change of the total pressure in the vessel = 787 torr/min increase since 1 mole SO2Cl2 dissociate to give 2 moles of product net 1 mole increase is there

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