(a) Consider the chlorination of methane, given below: 1 CH4(g) + 4 Cl2(g) 1 CC1
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Question
(a) Consider the chlorination of methane, given below: 1 CH4(g) + 4 Cl2(g) 1 CC14(g) + 4 HCl(g) If CH4(9) is decreasing at the rate of 0.940 mol/s, what are the rates of change of Cl2 g), CCl4(9), and HCl(g)? of change of Clz(g). cCiMlo), and HCI(9) mol/s mol/s mol/s (b) The decomposition reaction given below: 3 NO(g) 1 N20(g)-1 NO2(g) is carried out in a closed reaction vessel. If the partial pressure of NO(g) is decreasing at the rate of 796 torr/min, what is the rate of change of the total pressure in the vessel? torr/minExplanation / Answer
1. The rate of decreasing of CH4 is 0.940 mol/s.
According to reaction 1 mol of CH4 reacts with 4 of Cl2 and produces 4 of HCl so:
0.940 x 4 = 3.76 mol/s for Cl2 and HCl.
In the case of CCl4, produces 1 mole, so the rate of change would be 0.940 mol/s.
2) 3 moles of NO produces 1 mole of N2O and NO2, so the rate of pressure for both of them would be:
796/3 = 265.33 torr/min.
The total pressure change would be: Products -. Reactants
Total pressure: (265.33 + 265.33) - 796 = -265.34 torr/min.
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