Help needed ASAP In a cross between two doubly heterozygous Ursa gummi, we obser
ID: 60012 • Letter: H
Question
Help needed ASAP
In a cross between two doubly heterozygous Ursa gummi, we observe 425 Brave Ursa gummi and 677 Timid Ursa gummi. If the Brave phenotype is the dominant phenotype, make a decision as to whether these data are consistent with the duplicate recessive epistatic mode of inheritance. Make your decision based on a significance level threshold of 5%.
A. Decision is: no, they are not. Chi-square p-value < 0.05.
B. Decision is: Yes, they are. Chi-square p-value < 0.05.
C. Decision is: Yes, they are. Chi-square p-value > 0.05.
D. Decision is: no, they are not. Chi-square p-value > 0.05.
E. Decision is: no, they are not. The mode of inheritance is Recessive Epistasis.
A. Decision is: no, they are not. Chi-square p-value < 0.05.
B. Decision is: Yes, they are. Chi-square p-value < 0.05.
C. Decision is: Yes, they are. Chi-square p-value > 0.05.
D. Decision is: no, they are not. Chi-square p-value > 0.05.
E. Decision is: no, they are not. The mode of inheritance is Recessive Epistasis.
Explanation / Answer
Answer: Option A.
Chi-square value is less than 0.05. This is because the expected and observed values are opposite.
Though the ratio of 425 and 677 is also 9:7, which represents duplicate recessive epistaisis, but here 9 represents the recessive trait- TIMID and 7 for dominant- Brave, which is opposite the expected value.
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