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Help needed ASAP, Please Agapanthus is a dominant, homozygous leth al trait amon

ID: 65493 • Letter: H

Question

Help needed ASAP, Please

Agapanthus is a dominant, homozygous lethal trait among Telorites from the planet Teleflora. Subjects with this condition love to send flowers. From a group of Telorites heterozygous at the Agapanthus locus (with two alleles: A = dominant (trait) allele, a = recessive (wild-type) allele), 88% of the Telorites have the Agapanthus phenotype, and 12% look wild-type.

Also, true-breeding wild-type Telorites (aa genotype) have 0% penetrance.

A Telorite with the Agapanthus phenotype mates with a true-breeding Telorite with the wild-type phenotype. One of the F1 children is randomly selected and is mated back to the true-breeding wild-type parent. Out of twenty F2 individuals, we observe the following counts:

Eight F2 individuals have the Agapanthus phenotype;

Twelve F2 individuals have the Wild-type phenotype.

The genotype of the randomly-selected F1 subject must be:

A. AA.

B. Aa.

C. Aa or aa.

D. We cannot say with certainty. We need to perform a Chi-square goodness of fit test.

E. aa.

A. AA.

B. Aa.

C. Aa or aa.

D. We cannot say with certainty. We need to perform a Chi-square goodness of fit test.

E. aa.

Explanation / Answer

The possibility of AA genotype is impossible because it is lethal in homozygous state

B.) Aa

Aa X aa

Aa (50% or 0.50) ; aa (50% or 0.50)

Progeny

Frequency

Penetrance of A

A phenotype

a phenotype

Aa

0.50

0.88

0.88 x 0.50 = 0.44 = 4.0 / 100

0.50 – 0.44 = 0.06

aa

0.50

0.0

0.50

total

8 / 20

0.56 = 0.60 / 100 = 12 / 20

Progeny

Frequency

Penetrance of A

A phenotype

a phenotype

Aa

0.50

0.88

0.88 x 0.50 = 0.44 = 4.0 / 100

0.50 – 0.44 = 0.06

aa

0.50

0.0

0.50

total

8 / 20

0.56 = 0.60 / 100 = 12 / 20