Consider the following data: 2 Ca(s) + O2(g) 2 CaO(s) Ho = -1270.2 kJ CO2(g) C(s

Question

Consider the following data: 2 Ca(s) + O2(g) 2 CaO(s) Ho = -1270.2 kJ CO2(g) C(s) + O2(g) Ho = +393.5 kJ CaCO3(s) CaO(s) + CO2(g) Ho = +178.3 kJ Use Hess's law to calculate Ho for the reaction below. Pick the choice which gives this Ho value. 2 CaCO3(s) 2 C(s) + 2 Ca(s) + 3 O2(g) a) Ho = -1055.0 kJ b) Ho = -1485.4 kJ c) Ho = 2413.8 kJ d) Ho = 1842.0 kJ e) Ho = -698.4 kJ

Explanation / Answer

2 Ca(s) + O2(g)---> 2 CaO(s) Ho = -1270.2 kJ CO2(g) ------>C(s) + O2(g) Ho = +393.5 kJ CaCO3(s) ----->CaO(s) + CO2(g) Ho = +178.3 kJ 2 CaCO3(s) ------> 2 C(s) + 2 Ca(s) + 3 O2(g) -reaction 1 + 2* reaction 2 + 2* reaction 3 = Desired reaction H = 1270.2 + 2* 393.5 + 2*178.3 = c) 2413.8

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