What is the solubility of Ca(OH)2 in 0.0500 M NaOH assuming both Ideal and Real

Question

What is the solubility of Ca(OH)2 in 0.0500 M NaOH assuming both Ideal and Real behavior?

Explanation / Answer

The solubility equation is: Ca(OH)2 ---> Ca2+ + 2 OH- Thus, adding CaCl2 or NaOH will affect the equilibrium of this reaction by driving the reaction further to the reagent side. In terms of equations, each situation can be expressed the following way: a) For x moles of calcium chloride added you have x moles of Ca2+ in solution and the equilibrium will shift to the left: Ca(OH)2 ---> Ca2+ + 2 OH- x + i/2 i where i is the amount at equilibrium (before adding CaCl2) and x is the amount of CaCl2 (in moles). In most cases i

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