Given that 3.582 g of copper (II) chloride are dissolved in 2.478 litres of deio

Question

Given that 3.582 g of copper (II) chloride are dissolved in 2.478 litres of deionized water, answer the following: 1) How many moles of copper (II) ions are present in the sample? 2) How many total copper (II) ions are present in sample? 3) What is the molar concentration of chloride ion in the final solution (assuming complete dissociation)? 4) What is the percentage yield if 122.5 mg of a light blue-green solid is collected after 100.00 mL of this solution is combined with 25.0 mL of 0.0433 M Na3PO4 solution? (You must calculate the theoretical yield for the reaction).

Explanation / Answer

Here is the formula and method of calculation of percentage yield In chemistry, the reaction yield is the amount of product produced by a chemical reaction. The theoretical yield is the maximum amount of product that can be produced in a perfectly balanced reaction, but the actual yield is usually less than the theoretical yield. To express the efficiency of a reaction, calculate the percent yield using this formula: %yield = (actual yield/theoretical yield) x 100

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