A botanist is investigating a population of plants whose petal color is controll

Question

A botanist is investigating a population of plants whose petal color is controlled by a single gene whose two alleles show incomplete dominance. She finds 170 plant that are homozygous brown, 340 plants that are homozygous purple, and 21 plants whose petals are brown-purple. Is this population in Hardy-Weinberg equilibrium?

I am not sure If I am doing correct. Can you please check my work and see if this is correct? If not, please explain. Thank you!

                   Since 1.85 is not equal to 1 then this population is not in Hardy-Weinberg equilibrium.

Explanation / Answer

170 + 340 + 21 = 531

Freq. of brown (BB) = p2 = 170/531 = 0.32

Freq. of purple-brown (B1B) = 2pq = 21/531 = 0.04

Freq. of purple (B1 B1) = q2 = 340/531 = 0.64.

p2 + 2pq + q2 = 1

0.32 + 0.64 + 0.04 = 1

1 = 1

The given population is in HW equilibrium.

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