What is the de Broglie wavelength in meters of a mosquito weighing 1.55mg and fl

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Explanation / Answer

5.85E19*6.626E-34= 3.87621E-14 J/photon * mole of photons= 2.33430793E10 Joules/mole divided by 1000 J/kJ= 2.33E7 kJ/mol 2. Doing the same yields 8.74632E-28 J/photon--> 0.000526715635 J/mol--> 5.26715635E-7 kJ/mol 3. Here we have to convert wavelength to frequency ,then do the same as above. Speed=Wavelength*Frequency, so Frequency is the quotient between the speed of light (3E8 m/s) and the wavelength of 246 m. This yields a frequency of 1,219,512.2 Hz. Plugging this in yields: 8.08048784-28 J/photon---> 0.00048661829 J/mol--> 4.8661829-7 kJ/mol De Broglie wavelength is given by h/p, where h is planck's constant of 6.626E-34 J/s, and p is the momentum of the object, given in kg-m/s. To calculate the momentum of the fly, we must convert it's mass into kilograms. 1.55 mg/1000 mg/kg yields .00155 kg. This mass multiplied by the velocity of 1.30 m/s results in a momentum of 0.002015 kg-m/s. The debroglie wavelength will be 6.626E-34 J/s divided by 0.002015 kg-m/s: 3.28833747 E-31 m, a very, very, very low number. Approximately 10,000 trillionths the size of a standard nucleus, which is measured on the femtometer scale (10^-15 m).

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