pls A bacterial cell is actively growing in an isotonic solution at 0.85% Nacl.
ID: 61808 • Letter: P
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pls A bacterial cell is actively growing in an isotonic solution at 0.85% Nacl. The cell is then placed into a higher salt concentration at 5.5% Nacl and steps growing and replacing If te 0.85 NaCl solution is isotonic for this cell, what is the appropriated term for the 5.5 Nacl solution? What is the most likely reason that the bacterial cell has stopped growing growth? Explain the movement of solute or solvent between the cell and its environment when into the 5.5% NaCl solution (remember osmosis!) 1. Would you make a salad with the spinach from short answer question #3 Use the following choices to answer question 2 and 3. E. coli growing in glucose broth at 37 C with O2 for 2 days E. coli growing in glucose broth at 37 C with O2 for 2 days All of the above None of the above 2. Which culture produces the most lactic acid? 3. Which culture generates the most ATP?Explanation / Answer
5.(a). If the 0.85% is isotonic then 5.5% Nacl is said to be hypertonic.
(b). In hypertonic condition, the cells stop to grow as they have been moved from a isotonic solution to a medium with higher solute concentration (lower water concentration). In order to attain equilibrium, water from cell move outside. As cell lose water, they will shrink and loss the capacity to divide and grow.
(c). When the cells from 0.85% Nacl (isotonic) have been moved to 5.5% Nacl (Hypertonic), the solvent in order to attain equilibrium moves from higher water concentration (but lower solute) to lower water concentration (but higher solute) and there by the cells shrinks.
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