Calculate the volume of air at 26 degrees Celsius and 0.92 atmosphere that is ne

Question

Calculate the volume of air at 26 degrees Celsius and 0.92 atmosphere that is needed to burn completely 11.47 grams of pentane. Assume that air is 21.0 percent O2 by volume

Explanation / Answer

T = 26 c = 299K P = 0.92 atm C5H12 + 8O2 --> 6H2O + 5CO2 so 72gms of pentane needs 256gms of O2 so weight of O2 required for 11.47 gms = 40.78gms no of moles = 40.78/32 so volume of O2 required = nRT/P = (40.78/32)*0.082*299/0.92 = 33.96 L so volume of air needed = (100/21)*33.96 = 161.72 so 161.72 Liters of air is neede under given conditions to butn 11.47gms of pentane

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