Calculate the value of H° for the following reaction: P 4 O 10 (s) + 6PCl 5 (g)

Question

Calculate the value of H° for the following reaction: P4O10(s) + 6PCl5(g) ---> 10Cl3PO(g)

P4(s) + 6Cl2(g) ---> 4PCl3(g)

H° = -1225.6 kJ

P4(s) + 5O2(g) ---> P4O10(s)

H° = -2967.3 kJ

PCl3(g) + Cl2(g) ---> PCl5(g)

H° = -84.2 kJ

PCl3(g) + (1/2)O2(g) ---> Cl3PO(g)

H° = -285.7 k

please explain well i do not understand these kind of problems

P4(s) + 6Cl2(g) ---> 4PCl3(g)

H° = -1225.6 kJ

P4(s) + 5O2(g) ---> P4O10(s)

H° = -2967.3 kJ

PCl3(g) + Cl2(g) ---> PCl5(g)

H° = -84.2 kJ

PCl3(g) + (1/2)O2(g) ---> Cl3PO(g)

H° = -285.7 k

Explanation / Answer

Calculate the value of H° for the following reaction: P 4 O 10 (s) + 6PCl 5 (g)

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