Question 1 consider your ln(rate) vs. 1000/T graph. Was teh data evenly distribu

Question

Question 1 consider your ln(rate) vs. 1000/T graph. Was teh data evenly distributed around the line or does the low (or high temperature endof the curve have more scatter than the other. is this result consistent with your observation? explain. question 2 The introduction state dthat often the rate doubles for each temperature increase of 10degree celcius. What value of the activation energy would cause the rate to double between 25~35degree celcius? ((k value???) question 3 In this experiment you used a red colorimetric guide to establish the end of the reaction. would you expect to get the same value of the activation energy if yellow was chosen rather than red? support your answer with your observations of the reaction. Question 4 How would you answer to question 3 differ if the frequency factor rather than the activation energy were considered?

Explanation / Answer

Arrhenius equation decribes temperuture-dependancy of the rate constant as: k = A · exp( -E/(R·T) The slope of the line in Arrhenius-plot is the factor in the argument of the exponential function: -E/R = -5.48×10³K Hence: k = A · exp(-5.48×10³K/T) A = k · exp(5.48×10³K/T) = 4190M?¹s?¹ · exp(5.48×10³K/760K) = 5.67×106M?¹s?¹ Note: The units you provided for the answer are not correct. Pre-exponential factor has the same unit as the rate constant.

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