There are three sources of protons to be considered in calculating the pH of a s

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H2O -----> H+ + OH- HAc -----> H+ + Ac- ; [H+] = sqrt (Ka * c) HCl ----> H+ + Cl- ; [H+] = 10^-8 Ka of total equation = kw * Ka of HAc * 1(Ka of HCl) = 1.8*10^-5 * 10^-14 = 1.8*10^-19 H2O + HCl + HAc -----> H+ + Ac- + OH- + Cl- [H+][Ac-][OH-][Cl-] = 1.8*10^-19 (10^-8 + x + y)*y*x*10^-8 = 1.8*10^-19 Also, (10^-8 + x + y)*x = 10^-14 y = 1.8*10^-5 x = 9.989 * 10^-10 Max H+ from HAc, then HCl then H2O HAc > HCl > H2O

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