Given the following reaction: 2CrO4^2-(aq) + 2H^+(aq) <---> Cr2O7^2-(aq)+H2O(l)

Question

Given the following reaction: 2CrO4^2-(aq) + 2H^+(aq) <---> Cr2O7^2-(aq)+H2O(l) Yellow orange a. What color would a K2CrO4 solution be? b. If sulfuric acid (H2SO4) is added to this solution, will a color change be observed? If so, how does the addition of sulfuric acid result in a color change? Explain your reasoning by showing the effect of the addition of H2SO4 on the equilibrium for the reaction. c. If sodium hydroxide (NaOH) is added to the solution, will a color change be observed? If so, how does the addition of sodium hydroxide result in a color change? Explain your reasoning by showing the effect of the addition of NaOH on the equilibrium for the reaction.

Explanation / Answer

follow this The reaction is: 2CrO42?(aq) + 2H+(aq) Cr2O72?(aq) + H2O(l) ref: http://en.wikipedia.org/wiki/Chromate as you add acid you will drive the reaction to the right forming more Cr2O7-2 which is red as you add base you will force the reaction to the left forming more CrO4-2 which is yellow

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