The complete reaction of glucose (1 molecule) breakdown by aerobic respiration o

Question

The complete reaction of glucose (1 molecule) breakdown by aerobic respiration of mammalian cells is written below: C6H12O6 (glucose) + 6O2 + 6H2O 6CO2 + 12H2O i) (2 points) Define the oxidation state of carbon atom and oxygen atom in the reaction. How many high energy electrons will be taken away from 1 molecule of glucose when it is completely broken down to carbon dioxide? How many electrons does each oxygen atom accept when it is reduced? (Reactions are not balanced)

C6H12O6 (glucose) 6CO2 Oxidation state of: C ________ C _________ How many electrons?______

6O2 12H2O Oxidation state of: O ________ O _________ How many electrons? ______

Explanation / Answer

C6H12O6 (glucose) : The oxidation number of Carbon atom is zero. This is because 12 H's (+1) balance 6 O's (-2).

6CO2: The oxidation number of Carbon atom is +4 because oxidation number of oxygen atom in O2 is 0.

Electrons lost by carbon: To get from zero to +4, each C has to lose 4 electrons. or, 6 carbons must lose 24 electrons.

6O2: The oxidation number of oxygen atom is 0. So, no net gain of electrons.

12H2O: The oxidation state of oxygen atom is always -2 in compounds, except in peroxides (like H2O2), where it is -1. So, 12 oxygen atoms atoms are needed to accept 24 electrons.

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