The distinctive portion of each amino acid is its... A)N-terminus, B) C-terminus
ID: 63157 • Letter: T
Question
The distinctive portion of each amino acid is its...
A)N-terminus, B) C-terminus, C) R-group, D)peptide bond
The coding segment of a eukaryotic gene starting from the beginning of the start codon to the end of the stop codon is 1002 base pairs. The gene also has two introns, one 50bp and another 49bp. How many amino acids would be present in the protein encoded by this gene?
A)300, B)301, C)333, D)900, E)903
The genetic code is a triplet code which is the minimal number of nucleotides necessary to code for 20 different amino acids ie. 1 nucleotide code could code for 4 different amino acids, 2 nucleotide code could code for 16 different amino acids.
If instead of there being 4 different nucleotides in DNA (ATCG), there were only 2 different nucleotides in DNA (eg A and T), then how many nucleotides (minimum) would have to be present in each codon to specify all 20 amino acids?
A)2, B)3, C)4, D)5, E)6 or more
Explanation / Answer
Q1). The distinctive portion of each amino acid is its...
C) R-group
Q2). The coding segment of a eukaryotic gene starting from the beginning of the start codon to the end of the stop codon is 1002 base pairs. The gene also has two introns, one 50bp and another 49bp. How many amino acids would be present in the protein encoded by this gene?
B)301
1002 base pairs- 334 amino acids
50 + 49= 99 base pairs----- 33 amino acids
334-33=301 amino acids
Q3). The genetic code is a triplet code which is the minimal number of nucleotides necessary to code for 20 different amino acids ie. 1 nucleotide code could code for 4 different amino acids, 2 nucleotide code could code for 16 different amino acids.
If instead of there being 4 different nucleotides in DNA (ATCG), there were only 2 different nucleotides in DNA (eg A and T), then how many nucleotides (minimum) would have to be present in each codon to specify all 20 amino acids?
E)6 or more
If 4 nucleotides are present, 64 codons (4X4X4) code for 20 amino acids.
If 2 nucleotides are present, 64 codons (2 X 2 X 2 X 2 X 2X 2) code for 20 amino acids
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