a- 4.00 L b- 13.4 L c- 11.2 L d- 22.4 L e- 5.60 L 2) For the following reaction,

Question

a-
4.00 L b-
13.4 L c-
11.2 L d-
22.4 L e-
5.60 L

2) For the following reaction, if 11.2 L of nitrogen are reacted to form NH3 at STP, How many liters of hydrogen will be required to completely consume all of the nitrogen?
N2 + 3H2 ? 2NH3 Answer a-
7.4 L b-
11.2 L c-
33.6 L d-
6.1 L e-

16.8 L

3)

1. 4 PCl3 (l) ? P4 (s) + 6 Cl2 (g) ?H = 304.0 kcal
   
   Based on the reaction shown, which statement is true? Answer a-
   
   When 123.88 g P4 (s) are produced, 304.0 kcal are released. b-
   When 137.14 g PCl3 (l) react, 304.0 kcal are consumed. c-
   When 1 mol P4 (s) is produced, 304.0 kcal are consumed. d-
   When 1 mol PCl3 (l) reacts, 304.0 kcal are released. e-
   When 548.56 g PCl3 (l) react, 304.0 kcal are released.
   
   4) A process which is unfavorable with respect to enthalpy, but favorable with respect to entropy Answer a-
   could occur at low temperatures, but not at higher temperatures. b-
   could not occur regardless of temperature. c-
   could occur at high temperatures, but not at lower temperatures. d-
   could occur at any temperature. e-
   none of the above 5) Consider the endothermic reaction:
   
   N2 (g) + 2 H2 (g) ? N2H4 (l)
   
   The entropy change of this reaction is ________ and the enthalpy change is ________, so at a very high temperature, this reaction is probably ________. Answer a-
   unfavorable; unfavorable; spontaneous b-
   favorable; unfavorable; spontaneous c-
   unfavorable; favorable; spontaneous d-
   favorable; unfavorable; nonspontaneous e-
   unfavorable; unfavorable; nonspontaneous
   
   6) Consider the reaction shown:
   
   304.0 kcal + 4 PCl3 (l) ? P4 (s) + 6 Cl2 (g)
   
   When 50.00 g of PCl3 react, ________ kcal will be ________. Answer a-
   304.0; produced b-
   304.0; consumed c-
   27.67; consumed d-
   110.7; consumed e-
   27.67; produced
   
   
   

Explanation / Answer

1)

Oxygen is O2 (diatomic molecule).

O2 mol.mass = 2 x 16 = 32g/mol.
Mass / mol.mass = moles.
1 mole of a gas at STP occupies 22.4 L.

(8g / 32g/mol) x 22.4 L/mol = 5.60 Litres at STP.

2)volume related to moles

PV = nRT if T& P fixed (which they are at STP)


so you need 3x the amount of H2 thus

answer c) is correct

3)10

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