1. What kinds of compounds form electrolytes in solution? 2. If 13.5 g NaCI were
ID: 636591 • Letter: 1
Question
1. What kinds of compounds form electrolytes in solution? 2. If 13.5 g NaCI were dissolved in 250.0 g of water, what is the mass percent of NaCI in the solution? What is the mass percent of water in the solution? A certain saline solution is 2.00% Cl by mass. If you have 250 ml of this solution, how many g of KCI are in it? 3. What is the concentration of a solution with 2.00 moles of solute in 4.00 l of solution? 4. What is the concentration of a solution that has 15.0 g NaCl dissolved to a total of 750 ml? 5. 6. How many moles of NaCI are in 250.0 ml of a 0.35 M NaCl solution? 7. How many grams of KCN are in 10.0 ml of a 0.10 M solution? 8. How many ml of 12.0 M H2S04 are needed to make 500.0 ml of a 1.00 M solution? What happens to the freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it? 9. 10. What is the molality of a solution if 100.0 g of glucose (C&Hi20e;) were dissolved into 750. mL of water? 11. What is the boiling point of this solution? (ko H20 0.512 C/m) 12. What would the boiling point be if the same number of moles of CaBrz were 13. What would happen to red blood cells if they were put into a beaker of fresh 14. According to the following reaction: KHP+ NaOH> NaKP+ H20 used instead of glucose? water? Sea water? What is the concentration of the NaOH if it took 42.52 ml to titrate 0.835 g of KHP? (MM KHP 204.2 g/mol) 15. According to the following equation, how many ml of 0.15 M NaOH would be needed to titrate 10.00 ml of 0.500 M HCl? 16. What is the pH of a 0.33 M solution of HCI?Explanation / Answer
Answer 1 ionic compound
Answer 2 mass percentage= (mass of solute/total mass of solution)*100
Mass percentage= (13.5/13.5+250)*100 = 5.12%
Answer 3. 2%kcl= 2g/100ml
Then 250ml = = 250/100=2.5
So mass of kcl is 2*2.5=5 gram
Answer 4. Concentration= mole of solute/volume in litre
Concentration= 2/4= 0.5M
Answer 5 mole of nacl = 15g/58.44g/mol=0.257 mole
Concentration= 0.257/0.75L=0.343M
Answer 6 mole of nacl = molarity*volume
Mole= 0.35*0.25=0.0875 mole
Answer 7 mole of kcn= 0.10*0.01=0.001mole
Mass=65.12g/mol*0.001=0.065 gram
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