H,so, (Solution B) to produce a 75.0 wt% solution (Solution C). Solution A Flowm
ID: 637678 • Letter: H
Question
H,so, (Solution B) to produce a 75.0 wt% solution (Solution C). Solution A Flowmeter A Analyzer Solution C 75% H2SO4 90% H2SO4 Flowmeter B MIXER The flow rate and concentration of Solution A change periodically, so that it is necessary to adjust the flow rate of Solution B to keep the product H2SO, concentration constant. Flowmeters A and B have linear calibration plots of mass flow rate (m) versus meter reading (R), which pass through the following points: Flowmeter A:150 Iba/hRA-25 -500 lb/h, RA-70 200Iba/h R20 800 b/h, Rs-60 Flowmeter B: The analyzer calibration is a straight line on a semilog plot of %H2SO4(x) on a logarithmic scale versus meter reading (R.) on a linear scale. The line passes through the points (x-20%, R, 2 40) and (x-100%, R1-100). (a) Calculate the flow rate of Solution B needed to process 300 lbm/h of 55% H2SO4 (Solution A), and the resulting flow rate of Solution C. (The calibration data are not needed for this part.) (b) Derive the calibration equations for ma(RA), ms(Ru), and x(R). Calculate the values of RA. RB, and R, corresponding to the flow rates and concentrations of part (a). (e) The process technician's job is to read Flowmeter A and the analyzer periodically, and then to use for Ry in terms of RA and R,, and then check it by substituting the values of part (a). adjust the flow rate of Solution B to its required value. Derive a formula that the technician canExplanation / Answer
MA+MB=Mc
=>Mc=(300+MB) ________________________(1)
MA. xA+MBxB=Mcxc
=>300x0.55+MBx0.9=(300+MB) x0.75
=>MB=400lbm/hr
Flow meter A
MA = 150 lbm/hr RA = 25
MA = 500 lbm/hr RA = 70
By linear regression,
(MA(RA)-150) =
Solving above, we get
Flow meter B
MB = 200 lbm/hr RB =20
MB = 800 lbm/hr RB = 60
By linear regression,
(MB(RB)-200) =
Solving above, we get
Analyser
Rx = 4 x = 0.2 ln x = ln (0.2)
Rx = 10 x = 1 ln x = ln (1) = 0
Solving above equation,
(C)
To find equation, we put all the above equations in mass balance
MA. xA+MBxB=Mcxc
MA+MB=Mc
=>Mc=(300+MB) ________________________(1)
MA. xA+MBxB=Mcxc
=>300x0.55+MBx0.9=(300+MB) x0.75
=>MB=400lbm/hr
Flow meter A
MA = 150 lbm/hr RA = 25
MA = 500 lbm/hr RA = 70
By linear regression,
(MA(RA)-150) =
Solving above, we get
Flow meter B
MB = 200 lbm/hr RB =20
MB = 800 lbm/hr RB = 60
By linear regression,
(MB(RB)-200) =
Solving above, we get
Analyser
Rx = 4 x = 0.2 ln x = ln (0.2)
Rx = 10 x = 1 ln x = ln (1) = 0
Solving above equation,
(C)
To find equation, we put all the above equations in mass balance
MA. xA+MBxB=Mcxc
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