GAA CTA GTT ATT AGT CTA ATT GTT GAA AGT CTT GAT CAA TAA TCA GAT TAA CAA CTT TCA
ID: 63799 • Letter: G
Question
GAA CTA GTT ATT AGT CTA ATT GTT GAA AGT
CTT GAT CAA TAA TCA GAT TAA CAA CTT TCA
1. Assume that the lower strand of DNA is the template strand. Transcribe mRNA.
2. Using the letters, not the amoino acids from the codon table, translate mRNA.
3. Make a gene mutation by substituting one base for another. Use the letters from the codon table to translate the new mRNA strand. How does it compare to the original?
4. Make another gene mutation by addition (Add one base somewhere in the mRNA strand). Translate it.
5. Make another gene mutation by deletion. (Remove one base somehere in the mRNA strand). Translate it.
Explanation / Answer
1) DNA template strand: 3` - CTT GAT CAA TAA TCA GAT TAA CAA CTT TCA - 5`
mRNA: 5` - GAA CUA GUU AUU AGU CUA AUU GUU GAA AGU - 3`
2) Amino acid sequence: L D Q I S D I Q L S
3) mRNA with mutation 1: (purine to purine transition: A to G)
mRNA: 5` - GGG CUG GUU GUU GGU CUG GUU GUU GGG GGU - 3`
Amino acid sequence: P D Q Q P D Q Q P P
Previous amino acid sequence: L D Q I S D I Q L S
At positions 2, 3, 5 and 7 the amino acids are same in both original and mutated sequences and rest all differ in both the sequences.
4) mRNA with mutation 2: (Addition of an extra base 'C' between 4th and 5th amino acids)
mRNA: 5` - GGG CUG GUU CGU UGG UCU GGU UGU UGG GGG U - 3`
Amino acid sequence: P D Q A T R P T T P
Previous amino acid sequence: L D Q I S D I Q L S
The mutated and original amino acid sequence has same 2nd and 3rd amino acids and rest all amino acids differ in both sequences.
5) mRNA with mutation 3: (deletion of base U in the second codon)
mRNA: 5` - GAA CAG UUA UUA GUC UAA UUG UUG AAA GU - 3`
Amino acid sequence: L V N N Q I N N K
Previous amino acid sequence: L D Q I S D I Q L S
The first amino acid is same in both mutated and original sequences. In original sequence Q occurs in 3rd and 8th positions, where as in mutated sequence Q occurs in 5th position. In original sequence I occurs in 3rd and 7th positions while in mutated sequence I occurs in 6th position and rest all amino acids differ in both the original and mutated sequences.
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