1/ Construct a while() loop, which computes the sum of all multiples of 7 and 8

Question

1/ Construct a while() loop, which computes the sum of all multiples of 7 and 8 for numbers 1 - 500. Show all variable declarations.

2/ Construct a for() loop, which computes the sum of all multiples of 7 and 8 for numbers 1 - 500. Show all variable declarations.

3/ Construct a do-while() loop, which continues to prompt the user for an integer, and determines the sum of integers entered, until a prime number is encountered. The prime number should not be included in the sum. Show all variable declarations.

Explanation / Answer

1) int i = 1,sum=0;

while(i <= 500)

{

if(i%7== 0 || i%8==0)

{

sum += i;

}

i++;

}

2)

int sum =0;

for(int i = 1; i<= 500 ; i++)

{

if(i%7==0 || i%8==0)

sum += i;

}

3 )bool check(int num)

{

for(int i = 2; i< num/2; i++)

{

   if(num%i==0)

   {

return false;

}

}

return true;

}

int sum = 0, tempsum =0;

do{

sum = tempsum;

cin>>i;

tempsum+=i;

}while(check(i));

cout<<sum;

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