How to separate positive and negative count from the following code: #include<io

Question

How to separate positive and negative count from the following code:

#include<iostream>
using namespace std;
int main()
{
int count=0;
double num;
double positive=0;
double negative=0;

cout<<"Please enter 10 whole numbers:"<<endl;
do
{
    cin >> num;
    if (num<=0)
  
      negative = negative+num;
    else
      positive= positive+num;
    count++;
}
while (count<10);
cout<<"The sum of all postive numbers is:"<<" "<< positive<<endl;
cout<<"The sum of all negative numbers is:"<<" "<<negative<<endl;
cout<<"The sum of all numbers is:"<<" "<<positive+negative<<endl;
cout<<"The average of all positive numbers is:"<<" "<<positive/count<<endl;
cout<<"The average of all negative numbers is:"<<" "<<negative/count<<endl;
cout<<"The average of all numbers is:"<<" "<<(positive+negative)/count<<endl;
return 0;
  
  
  
  
  
  
  
  
}

Explanation / Answer

#include<iostream>
using namespace std;
int main()
{
int positiveCount=0;
int negativeCount=0;
int count = 0;
double num;
double positive=0;
double negative=0;

cout<<"Please enter 10 whole numbers:"<<endl;
do
{
cin >> num;
if (num<=0)
{
negative = negative+num;
negativeCount++;
}
else{
positive= positive+num;
positiveCount++;
}
count++;
}
while (count<10);
cout<<"The sum of all postive numbers is:"<<" "<< positive<<endl;
cout<<"The sum of all negative numbers is:"<<" "<<negative<<endl;
cout<<"The sum of all numbers is:"<<" "<<positive+negative<<endl;
cout<<"The average of all positive numbers is:"<<" "<<positive/positiveCount<<endl;
cout<<"The average of all negative numbers is:"<<" "<<negative/negativeCount<<endl;
cout<<"The average of all numbers is:"<<" "<<(positive+negative)/count<<endl;
return 0;
  

}

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