Consider the following class Grade: public class Grade { private char letterGrad

Question

Consider the following class Grade:

public class Grade
{

private char letterGrade;

public Grade( char 1g )
{

letterGrade = 1g;

}

public char getLetterGrade ( )
{
return letterGrade;

}

public void setletterGrade{ char 1g )
{
letterGrade = 1g;

}

}

Question:

In the main method of the class GradeClient. you have coded:

Grade g . new Grade{ 'B' ) ;
g.letterGrade = 'A ' ; // line 10

When you compile, you get the follow ing message:

GradeClient.java:l0: letterGrade has private access in Grade
g.letterGrade = 'A';

^

1 error

Explain what the problem is and how to fix it.

This is programming in Java the actual quesiton is in bold thank you

Explanation / Answer

Solution:

//The compilation error indicates the class Grade does not have a constructor that takes in an argument of type "String". So, while trying to instantiate the class Grade by calling a constructor, it is expecting a parameter of type "char" as per the code.

Grade g = new Grade('A'); //Pass 'A' as a char and not as "A" which is treated as a String

Corrected code here here:

public class Grade
{
private char letterGrade;

public Grade(char lg)
{
letterGrade = lg;
}

public char getLetterGrade( )
{
return letterGrade;
}

public void setletterGrade(char lg)
{
letterGrade = lg;
}

public static void main(String args[]) {
   Grade grade = new Grade('A');
   System.out.println("The grade is: "+grade.getLetterGrade());
}
}

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