Write a bash script that uses awk to display only the names, phone number, state

Question

Write a bash script that uses awk to display only the names, phone number, state and zip in a tabular format of the address book below.

$ cat addressbook

Xiao Li, lxiao, lxiao@unc.edu, 6705462234, Jackson, NC 764

Natkin William, wnatkin, wnatkin@imap28.vcu.edu, 8044344528, Richmond, VA 22345

Elizi Moe, emoe, emoe@ncsu.edu, 5208534566, Tempe, AZ 85282

Ma Ta, mta, mta@yahoo.com, 4345667345, Austin, TX 91030

Diana Cheng, dcheng, dcheng@asu.edu, 5203456789, Matitsi, WY 4587

Jackson Five, jfive, jfive@ncsu.edu, 5206564573, Kyenta, AZ 85483

Adi SrikanthReddy, sadi1, sadi1@imap1.asu.edu, 6578904566, Wyo, WS 67854

Explanation / Answer

#!/bin/bash

#file:d:/home/naman/tmp/phone.sh

#Description:Master script for phone book for program

Name of address book

BOOK="address-book.txt"

exit=0

while[$exit-ne1]

do

echo"What do you want to do"

echo -e"add,list,find,del,exist:"

read answer

if["$answer"="add"]

then

./add.sh

elif["$answer"="list"]

then

./list.sh

elif["$answer"="find"]

then

./find.sh

elif["$answer"="del"]

then

./del.sh

elis["$answer"="exit"]

then

exit=1

else

echo"I do not understand the coomand of the above language"

fi

done

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