1). On the planet Yado, there is a population of Lingkons. In this population, t
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Question
1). On the planet Yado, there is a population of Lingkons. In this population, there is a phenotype known as Eganro. Lingkons with this phenotype prefer fruit to vegetables. Wild-type individuals like all forms of food. Eganro is determined by a gene with two alleles (E = dominant (trait) allele, e = recessive (wild-type) allele). It is know that the gene for Eganro follows a homozygous-lethal dominant mode of inheritance with reduced penetrance (although the penetrance is not known with certainty). It is conjectured that the An affected Lingkon and a true-breeding unaffected Lingkon mate and produce 100 offspring. The numbers of affected and unaffected offspring are: 27 Eganro offspring; 73 Wild-type offspring. Which of the following values is the most like value for the penetrance of the Ee genotype?
A. 0.10. B. 0.75. C. 0.20. D. 0.44. E. 0.99.
2). Agapanthus is a dominant, homozygous lethal trait among Telorites from the planet Teleflora. Subjects with this condition love to send flowers. From a group of Telorites heterozygous at the Agapanthus locus (with two alleles: A = dominant (trait) allele, a = recessive (wild-type) allele), 88% of the Telorites have the Agapanthus phenotype, and 12% look wild-type.
Also, true-breeding wild-type Telorites (aa genotype) have 0% penetrance.
A Telorite with the Agapanthus phenotype mates with a true-breeding Telorite with the wild-type phenotype. One of the F1 children is randomly selected and is mated back to the true-breeding wild-type parent. Out of three F2 individuals, we only observe the wild-type phenotype.
The genotype of the randomly-selected F1 subject must be:
A. AA.
B. aa.
C. Aa.
D. We cannot say with certainty. We need to perform a Chi-square goodness of fit test.
E. Aa or aa.
A. AA.
B. aa.
C. Aa.
D. We cannot say with certainty. We need to perform a Chi-square goodness of fit test.
E. Aa or aa.
Explanation / Answer
1. D. 0.44.
2. A. AA.
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