Consider a mesh network connecting n devices. A) The total number of cables in t

Question

Consider a mesh network connecting n devices.

A) The total number of cables in the network is 55. What is n?

B) The link connecting two given devices has a bandwidth of 12 KHz and an SNR of 37. Calculate the theoretical capacity of this channel.

C) A sender S transmits fixed-length packets to a receiver R over a link in the network at 100 Kbps. The one-way propagation delay is 100ms. How much traffic, measured in bits, fills this link at a given time?

My Answers:

A):

Number of cables = n(n-1)/2

55(55-1)/2

55(54/2)

2970 / 2 = 1485 the number of devices connected via the mesh topology

B):

Shannon's Equation: C = B log2 (1 + SNR)

B = 12000 Hz

SNR = 37dB

SNR = 103.7

C = 12000 log2 (1+ 103.7)

C = 12000 log2 (5011.8)

C = 44399 bps

C):

I think i got A and B okay, but C i'm not sure how to do.

Thanks

Explanation / Answer

As you asked only third part you want to be done.....Already you solved first two questions.

traffic rate = capacity of bits/time interval

   = 100 kbps/100 ms = 100 * 1000/100 * 10-3 s

= 100 x 1000 bits/100ms = 100 x 1000 x 1000/100 sec = 10^6 bps

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