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Consider a non-periodic analog signal with a frequency spectrum from 1,200 to 7,

ID: 662629 • Letter: C

Question

Consider a non-periodic analog signal with a frequency spectrum from 1,200 to 7,100 Hz. The signal has 128 possible signal levels.

A) What is the theoretical maximum bit rate of the signal?

B) Assume the signal is initially transmitted at 20 milliwatts but travels over four hops, each of which has an attenuation of -2.2 dB. What is its power when finally received?

C) Assume the one-way propagation delay for a given link the signal travels over is 0.02 seconds. A sender S transmits fixed-length packets to a receiver R over this link at 2,100 packets per second. While full, the link suffers a sudden failure. What is the minimum number of packets that can be lost, and the maximum number of packets that can be lost? (A bit that has not arrived at the receiver at the time of the cut is lost, and a packet whose last bit has not arrived at the receiver at the time of the cut is lost.)

A)

The frequancy spectrum = f = 1200 to 7100 Hz

signal level =128

Theoretical bit rate = ?

We know that

Bit rate = R = 1 / Transmission time= 1 / Tb

Transmission time = Tb = 1 / f

Tb = 1 / 1200

Tb = 0.00083 sec

Putting in the equation of bit rate

BIt rate = R = 1/ 0.00083

= 1204.8bit/sec

B)

Final power received = Pr = ?

The relationship between transmitting power Pd, receiving power Pr and attenuation (Ap)is given below

Ap = 10 log10 Pd / Pr

Putting the values

Taking anti log on both sides

Pr = 0.0333watt

Pr = 33.33m watt

C)


I think I followed A & B correct, but not sure how to approach part C.

Explanation / Answer

C) Min. number of packets that can be lost = 2100/1200 = 1.75 =2 (approx)

Max. number of packets that can be lost = 7100 / 2100 = 3.38 =3 (approx)

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