Determine the end (final) value of n in ahydrogen atom transition if the electro
ID: 675626 • Letter: D
Question
Determine the end (final) value of n in ahydrogen atom transition if the electron starts at n = 2 and theatom absorbs a photon of light with an energy of 2.044 x 10-18J.The speed of sound in air is 344 m/s at room temperature. Thelowest frequency of a large organ pipe is 30.0 s-1 and the highestfrequency of a piccolo is 1.50 x 104 s-1. Find the difference inwavelength between these two sounds. Determine the end (final) value of n in ahydrogen atom transition if the electron starts at n = 2 and theatom absorbs a photon of light with an energy of 2.044 x 10-18J.
The speed of sound in air is 344 m/s at room temperature. Thelowest frequency of a large organ pipe is 30.0 s-1 and the highestfrequency of a piccolo is 1.50 x 104 s-1. Find the difference inwavelength between these two sounds.
Explanation / Answer
We Know trhat : According to Max-planckRelationship : E = n hv Given : E = 2.044 x 10-18 J n1 = ? n2 = 2 h = 6.627 x 10-34 J-s R = 1.0973 x 1013 m-1 C = 3.0 x 108 m s-1 E = hc R ( 1 / n1 2 - 1 / n22 ) Substituting the above values in the equation we get : 2.044x 10-18 J = 6.627 x10-34 J-s x 3.0 x 108 ms-1 x 1.0973 x 107 m-1 ( 1/ n1 2 - 1/ 22 ) n1 = 1 For the given values we cannot calculate final state of n . So by consdering the given value is for n2 ifwe calculate n1 we obtain the value as 1. We Know that For electromagneticRadiation : = V / 2 = 344 m / s / 30 s-1 = 11.47 m 1 = 344 m / s / 1.5 x 104 s-1 = 0.0229 m The difference in wavelengthsis 2 - 1 = 11.4471 m. = 11.47 m 1 = 344 m / s / 1.5 x 104 s-1 = 0.0229 m The difference in wavelengthsis 2 - 1 = 11.4471 m.Related Questions
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