what volumes of 500 mM HNO2 and 500 mM NaNO2 are required inorder to prepare a 1

Question

what volumes of 500 mM HNO2 and 500 mM NaNO2 are required inorder to prepare a 1000 mL buffer solution which has a pH=3.55. theKa for HNO2 is 4.3x10-4 just a little confused on how to do this question..any help isgreatly appreciated what volumes of 500 mM HNO2 and 500 mM NaNO2 are required inorder to prepare a 1000 mL buffer solution which has a pH=3.55. theKa for HNO2 is 4.3x10-4 just a little confused on how to do this question..any help isgreatly appreciated just a little confused on how to do this question..any help isgreatly appreciated

Explanation / Answer

pH = pKa + log ([A-]/[HA]) 3.55 = 3.37 + log ([A-]/[HA]) log([A-]/[HA]) = 0.18 [A-]/[HA] = 1.5136 / 1 Since the concentration of HNO2 and NaNO2 arethe same, we can ignore the concentration and calculate thevolume. Proportion of [A-] = 1.5136 / 2.5136 x 100 = 60.2% Volume of NaNO2 required = 1000 x 60.2% = 602mL Proportion of [HA] = 1 / 2.5136 x 100 = 39.8% Volume of HNO2 required = 1000 x 39.8% = 398mL Hope this helps!

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