W (g) + X (g) --> Y (g) +Z (g) Gases W and X react in a closed, rigid vessel to

Question

W(g) + X(g) --> Y(g) +Z(g) Gases W and X react in a closed, rigid vessel to form gases Yand Z according to the equation above. The initial pressure of W(g)is 1.20 atm and that of X(g) is 1.60 atm. No Y(g) or Z(g) isinitially present. The experiment is carried out at constanttemperature. What is the partial pressure of Z(g) when the partialpressure of W(g) has decreased to 1.0 atm? A) 0.20 atm B) 0.40 atm C) 1.0 atm D) 1.2 atm E) 1.4 atm W(g) + X(g) --> Y(g) +Z(g) Gases W and X react in a closed, rigid vessel to form gases Yand Z according to the equation above. The initial pressure of W(g)is 1.20 atm and that of X(g) is 1.60 atm. No Y(g) or Z(g) isinitially present. The experiment is carried out at constanttemperature. What is the partial pressure of Z(g) when the partialpressure of W(g) has decreased to 1.0 atm? A) 0.20 atm B) 0.40 atm C) 1.0 atm D) 1.2 atm E) 1.4 atm Gases W and X react in a closed, rigid vessel to form gases Yand Z according to the equation above. The initial pressure of W(g)is 1.20 atm and that of X(g) is 1.60 atm. No Y(g) or Z(g) isinitially present. The experiment is carried out at constanttemperature. What is the partial pressure of Z(g) when the partialpressure of W(g) has decreased to 1.0 atm? A) 0.20 atm B) 0.40 atm C) 1.0 atm D) 1.2 atm E) 1.4 atm

Explanation / Answer

The answer is A) .20 atm.

I really stink at explaining stuff (so I've been told) but thinkabout it in terms of Dalton's Law:

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