W + 2X <----> 5Y + 3Z 0.40 moles of W and 0.40 moles of X are placed into a 2.0

Question

W + 2X <----> 5Y + 3Z


0.40 moles of W and 0.40 moles of X are placed into a 2.0 liter flask. At equilibrium, 0.70 moles of Y are present in the flask. Calculate the concentration of each specie at equilibrium and calculate the value of equilibrium constant. W + 2X <----> 5Y + 3Z


0.40 moles of W and 0.40 moles of X are placed into a 2.0 liter flask. At equilibrium, 0.70 moles of Y are present in the flask. Calculate the concentration of each specie at equilibrium and calculate the value of equilibrium constant. W + 2X <----> 5Y + 3Z

Explanation / Answer

   conc of W = no of moles/volume in L

   = 0.4/2 = 0.2 M

conc of X    = no of moles/volume in L

                         = 0.4/2 = 0.2M

conc of Y           = no of moles/volume in L

                           = 0.7/2   = 0.35M

W   +    2X <----> 5Y     +    3Z

I         0.2      0.2            0      0

C     -0.07    -2*0.07     5*0.07       3*0.07

E      0.13       0.06        0.35          0.21

[Y]   = 0.35M

[Z] = 0.21M

[W] = 0.13M

[X]   = 0.06M

      Kc   = [Y]^5*[Z]^3/[W][X]^2

              = (0.35)^5*(0.21)^3/(0.13)(0.06)^2    = 0.104 >>>>answer

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