An unknown metal (M) reacts wuth hydrochloric acid (27.9 mL,2.48mol/L) according

Question

An unknown metal (M) reacts wuth hydrochloric acid (27.9 mL,2.48mol/L) according to this reaction: M(s) + 2HCl(aq) --> MCl2(aq) + H2(g) After the reaction was completed the solution was evaporatedto dryness leaving 4.72g of residue. What metal reacted? An unknown metal (M) reacts wuth hydrochloric acid (27.9 mL,2.48mol/L) according to this reaction: M(s) + 2HCl(aq) --> MCl2(aq) + H2(g) After the reaction was completed the solution was evaporatedto dryness leaving 4.72g of residue. What metal reacted?

Explanation / Answer

c(HCl) = n/v n(HCl) = cv = 2.48 x 0.0279 = 0.06919mol n(M) = 1/2 x n(HCl) = 0.034596mol n(M) = m/M 0.034596 = 4.72/M M = 136.43 g/mol From the periodic table, it is seen Barium has relative atomic massof 137.3, which is very close to 136.43 So, the metal reacted is Ba. Hope this helps!

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