The singleproton that forms the nucleus of a hydrogen atom has a radius ofapprox
ID: 676683 • Letter: T
Question
The singleproton that forms the nucleus of a hydrogen atom has a radius ofapproximately 1.0 X 10^(-13) cm {thisnumber is in scientific notation}. The hydrogen atom itself has aradius of 52.9 pm. What fraction of the space within
the atom is occupied by the nucleus? The singleproton that forms the nucleus of a hydrogen atom has a radius ofapproximately 1.0 X 10^(-13) cm {this
number is in scientific notation}. The hydrogen atom itself has aradius of 52.9 pm. What fraction of the space within
the atom is occupied by the nucleus?
Explanation / Answer
radius of proton = 1.0 * 10-13cm considering it as a sphere Volume of proton = (4/3) r3 =(4/3) (1.0 * 10-13 cm)3 =4.19 * 10-39 cm3 Radius of atom = 52.9 pm = 52.9 * 10-12 m =52.9 * 10-10 cm So volume of atom = (4/3) r3 =(4/3) (52.9 * 10-10 cm)3 = 2.21* 10-28 cm3 Fraction of space occupied by nucleus = Volume occupied bynucleus / Total volume of atom = 4.19 * 10-39 cm3 / 2.21 *10-28 cm3 =1.89 * 10-11 Radius of atom = 52.9 pm = 52.9 * 10-12 m =52.9 * 10-10 cm So volume of atom = (4/3) r3 =(4/3) (52.9 * 10-10 cm)3 = 2.21* 10-28 cm3 Fraction of space occupied by nucleus = Volume occupied bynucleus / Total volume of atom = 4.19 * 10-39 cm3 / 2.21 *10-28 cm3 =1.89 * 10-11 Fraction of space occupied by nucleus = Volume occupied bynucleus / Total volume of atom = 4.19 * 10-39 cm3 / 2.21 *10-28 cm3 =1.89 * 10-11Related Questions
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