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at a certain temperature , K= 9.1 x 10 -4 for thereaction FeSCN 2+ (aq) + <--> F

ID: 676899 • Letter: A

Question

at a certain temperature , K= 9.1 x 10-4 for thereaction FeSCN2+(aq)  +       <-->  Fe3+ (aq)   +         SCN-(aq) Calculate the concentrations of Fe3+,SCN-, and FeSCN2+ in a solution that isinitially 2.0 M FeSCN2+ at a certain temperature , K= 9.1 x 10-4 for thereaction FeSCN2+(aq)  +       <-->  Fe3+ (aq)   +         SCN-(aq) Calculate the concentrations of Fe3+,SCN-, and FeSCN2+ in a solution that isinitially 2.0 M FeSCN2+ Calculate the concentrations of Fe3+,SCN-, and FeSCN2+ in a solution that isinitially 2.0 M FeSCN2+

Explanation / Answer

We Know that :        FeSCN+2aq.   --------> Fe+3   + SCN-    initial Conc. : 2.0M             0              0     equilib. Conc.    -x              +x            +x                                    K   = [ Fe+3 ] [SCN- ]   /   [FeSCN+2  ]                 9.1 x 10-4   =   x X x /   2.0 - x     Let theVolume of the Reaction Vessel is 1.0 L               X2 + 9.1 x 10-4 X - 18.2 x10-4 = 0              By solving the above equation we get :            X = 0.0422          The Concnetration of   [ Fe+3 ]   = [ SCN- ]   = 0.0422 M                                                    [ FeSCN+2 ]   = 2 - 0.0422                                                                            = 1. 9578 M                              initial Conc. : 2.0M             0              0     equilib. Conc.    -x              +x            +x                                    K   = [ Fe+3 ] [SCN- ]   /   [FeSCN+2  ]                 9.1 x 10-4   =   x X x /   2.0 - x     Let theVolume of the Reaction Vessel is 1.0 L               X2 + 9.1 x 10-4 X - 18.2 x10-4 = 0              By solving the above equation we get :            X = 0.0422          The Concnetration of   [ Fe+3 ]   = [ SCN- ]   = 0.0422 M                                                    [ FeSCN+2 ]   = 2 - 0.0422                                                                            = 1. 9578 M