at a certain temp, K eq = 0.0211 for the equilibriumPCl 5 (g0 --- PCl 3 (g) =Cl

Question

at a certain temp, Keq = 0.0211 for the equilibriumPCl5(g0 --- PCl3(g) =Cl2(g). A. What is [Cl2] in an equilibrium mixturecontaining 0.865 mol/L PCl5 and 0.135 mol/LPCl3? B. What is [PCl5] in an equilibrium mixturecontaining 0.100 mol/L PCl3 and 0.200 mol/LCl2? at a certain temp, Keq = 0.0211 for the equilibriumPCl5(g0 --- PCl3(g) =Cl2(g). A. What is [Cl2] in an equilibrium mixturecontaining 0.865 mol/L PCl5 and 0.135 mol/LPCl3? B. What is [PCl5] in an equilibrium mixturecontaining 0.100 mol/L PCl3 and 0.200 mol/LCl2?

Explanation / Answer

We Know that :       The given Reaction is :          PCl5 ----------> PCl3 + Cl2             Kc = [ PCl3 ] [Cl2] / [PCl5]         0.0211 = 0.135 M [ Cl2] /   0.865 M             [ Cl2]   = 0.1351 M     B.             0.211 = 0.100 M x 0.200 M / [PCl5 ]                 [PCl5]  =   0.094 M             Kc = [ PCl3 ] [Cl2] / [PCl5]         0.0211 = 0.135 M [ Cl2] /   0.865 M             [ Cl2]   = 0.1351 M     B.             0.211 = 0.100 M x 0.200 M / [PCl5 ]                 [PCl5]  =   0.094 M

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