The rate of a reaction was measured at different temperaturesand the following d

Question

The rate of a reaction was measured at different temperaturesand the following data were obtained: Temperature(Celcius)             Reaction Rates (s-1) 20.0                                             0.77 50.0                                            2.91 Calculate the activation energy of the reaction inkJ/mol Thanks so much for your help! The rate of a reaction was measured at different temperaturesand the following data were obtained: Temperature(Celcius)             Reaction Rates (s-1) 20.0                                             0.77 50.0                                            2.91 Calculate the activation energy of the reaction inkJ/mol Thanks so much for your help! 20.0                                             0.77 50.0                                            2.91 Calculate the activation energy of the reaction inkJ/mol Thanks so much for your help!

Explanation / Answer

Formula :                   ln(k1/k2 ) = Ea /R ( 1/T2 -1/T1) Where k1 is the first order rate constant at T1           k2 is the first order rate constant at T2           Ea is the activation energy            Ris the gas constant Data :          k1 = 0.77 s-1          T1 = 273 + 20 K                = 293 K          k2  = 2.91 s-1
         T2  = 323 K Upon substituting in the above equation ,        ln ( 0.77 / 2.91) = Ea / 8.314 J / mol.K ( 1/323 K - 1/ 293 K)                 -1.32        = Ea * -3.8*10^-5                            Ea = 1.32 / 3.8*10^-5                                 = 34.62 kJ / mol

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