How many grams ofethylene glycol, C2H4(OH)2, must be dissolved in 2000.0grams of

Question

How many grams ofethylene glycol, C2H4(OH)2, must be dissolved in 2000.0grams of water to lower the preezing point to -29.75 deg C? If thedensity of ethylene glycol is 1.12 g/mL, how many milliliters ofethylene glycol are required? I need to verify the work...please help How many grams ofethylene glycol, C2H4(OH)2, must be dissolved in 2000.0grams of water to lower the preezing point to -29.75 deg C? If thedensity of ethylene glycol is 1.12 g/mL, how many milliliters ofethylene glycol are required? I need to verify the work...please help I need to verify the work...please help

Explanation / Answer

Since freezing point of water = 0 C, Freezing point depression, Tf = 29.75 C Kf for water = 1.86 C/m So molality of ethylene glycol = Tf / Kf                                              =29.75 C / 1.86 C/m                                             = ˜ 16 m Molality = Mass of solute * 1000 g / ( Molar mass * Mass ofsolvent ) 16 m = Mass * 1000 / (62.06 g/mol * 2000 g) So mass of ethylene glycol = 1985.92 g Density = 1.12 g/mL So Volume of ethylene glycol = Mass / density                                              =1985.92 g/ 1.12 g/mL                                              =1773.14 mL

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