A vessel originallycontained 0.180 mol iodine monbromide (IBr), 0.000400 molI2,

Question

A vessel originallycontained 0.180 mol iodine monbromide (IBr), 0.000400 molI2, and
0.000400 mol Br2.
I2(g) +Br2(g) 2IBr(g)
The equilibrium constant KCfor this reaction is 1.2× 102at 150 ºC.(a)What is the value of the reactionquotient, QC?(b)Will more or less IBr form? You must show the complete calculationfor full credit. More / Less IBr willform (circle the correct word). A vessel originallycontained 0.180 mol iodine monbromide (IBr), 0.000400 molI2, and
0.000400 mol Br2.
I2(g) +Br2(g) 2IBr(g)
The equilibrium constant KCfor this reaction is 1.2× 102at 150 ºC.(a)What is the value of the reactionquotient, QC?(b)Will more or less IBr form? You must show the complete calculationfor full credit. More / Less IBr willform (circle the correct word).

Explanation / Answer

                                              I2(g) +Br2(g) 2IBr(g)
                                                 Q = [IBr]2 / [I2][Br2]                                                       = ( 0.180 ) ^ 2 / ( 0.00040 )( 0.00040 )                                                       = 202500                                                       = 2.025 * 10 ^ 5                                              Kc    = 1.2 * 10 ^ 2                                              Q > Kc , more IBr will be formed . Now equilibrium shiftstowards left .

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