Estimate H for the reaction H202+CH3OH--->H2CO +H2O,given the following bondener

Question

Estimate H for the reaction H202+CH3OH--->H2CO +H2O,given the following bondenergies;       C-C 347 kJ/mol      A. -105kJ C=C 614 kJ/mol      B. 345kJ C-O 358 kJ/mol     C.-199kJ C=O 799 kJ/mol      D.-345kJ C-H 413 kJ/mol      E. 199kJ O-H 463 kJ/mol O-O 146 kJ/mol Estimate H for the reaction H202+CH3OH--->H2CO +H2O,given the following bondenergies;       C-C 347 kJ/mol      A. -105kJ C=C 614 kJ/mol      B. 345kJ C-O 358 kJ/mol     C.-199kJ C=O 799 kJ/mol      D.-345kJ C-H 413 kJ/mol      E. 199kJ O-H 463 kJ/mol O-O 146 kJ/mol

Explanation / Answer

The balanced equation is     H2O2   +     CH3OH   --->   H2CO + 2 H2O H rxn = Bond energies of reactents - Bond energies of products             = [3(O-H) + (O-O) + 3 (C-H) + (C-O) ]    - [(C=O) + 2 (C-H) + 4 ( O-H) ]             = [ 3(463 kJ) + 146 kJ + 3 (413 kJ) + 358 kJ ] - [ 799 kJ + 2(413 kJ) + 4 ( 463) ]             =-345 kJ Ans: D

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