The reaction betweengaseous substances C and D proceeds at a measurable rate. Th

Question

The reaction betweengaseous substances C and D proceeds at a measurable rate. Thefollowing set of data has been accumulated for the reaction 3C+2D 2F+G Expt    [C]M     D[M]       Rate of appearance of F(mol/h) 1         0.010     1.0                  .3 x 10-7 2          0.010      3.0                  2.7x 10-7 3         0.020     3.0                  10.8x 10-7 4         0.020     1.0                   1.2x 10-7 5         0.030     3.0                  24.3 x 10-7 a. What is the order of the reaction with respect to substanceC? substance D? b Write the rate expression for the reaction. c. Waht is the numerical value of the rate constant k? d. What is the rate of appearance of F when [C] = 0.050 M and[D]= 2.0 M? The reaction betweengaseous substances C and D proceeds at a measurable rate. Thefollowing set of data has been accumulated for the reaction 3C+2D 2F+G Expt    [C]M     D[M]       Rate of appearance of F(mol/h) 1         0.010     1.0                  .3 x 10-7 2          0.010      3.0                  2.7x 10-7 3         0.020     3.0                  10.8x 10-7 4         0.020     1.0                   1.2x 10-7 5         0.030     3.0                  24.3 x 10-7 a. What is the order of the reaction with respect to substanceC? substance D? b Write the rate expression for the reaction. c. Waht is the numerical value of the rate constant k? d. What is the rate of appearance of F when [C] = 0.050 M and[D]= 2.0 M? a. What is the order of the reaction with respect to substanceC? substance D? b Write the rate expression for the reaction. c. Waht is the numerical value of the rate constant k? d. What is the rate of appearance of F when [C] = 0.050 M and[D]= 2.0 M?

Explanation / Answer

a. Order of C: Use experiment 1 and 4 [D] stays the same at 1.0, the [C] doubles from .01 to .02, and therate quadruple. So order of C is 2 Order of D: use experiment 1 and 2 [C] stays the same at .010, the [D] triples from 1.0 to 3, and therate nine times the original. So order of D is 2 b. rate = k [c] 2 [d]2 c. Pick any experiment, I'm just going to useexperiment 1. .3e-7 = k[.012][1.02] k = .0003 d. rate = k [c] 2 [d]2 rate = (.0003)(.052)(2.02) rate = 3.0 x 10-6

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