Calculate the H 0rxn for H2 (g) +F2 (g) ---> 2HF (g). A)-271.6 kJ/mol B)-543.2 k

Question

Calculate the H0rxn for H2 (g) +F2 (g) ---> 2HF (g). A)-271.6 kJ/mol B)-543.2 kJ/mol C)+271.6 kJ/mol D)0 kJ/mol E)-135.8 kJ/mol (My guess is that the answer is zero..... but I might be wrongbecause the products are not in their standard state. Or arethey???) I do not know what the right answer is at themoment. Thanks for your help!) Calculate the H0rxn for H2 (g) +F2 (g) ---> 2HF (g). A)-271.6 kJ/mol B)-543.2 kJ/mol C)+271.6 kJ/mol D)0 kJ/mol E)-135.8 kJ/mol (My guess is that the answer is zero..... but I might be wrongbecause the products are not in their standard state. Or arethey???) I do not know what the right answer is at themoment. Thanks for your help!) Calculate the H0rxn for H2 (g) +F2 (g) ---> 2HF (g). A)-271.6 kJ/mol B)-543.2 kJ/mol C)+271.6 kJ/mol D)0 kJ/mol E)-135.8 kJ/mol (My guess is that the answer is zero..... but I might be wrongbecause the products are not in their standard state. Or arethey???) I do not know what the right answer is at themoment. Thanks for your help!)

Explanation / Answer

Horxn = Hf products - Hf reactants             =[2( Hf ( HF)) ] - [ Hf (H2) + HF (F2)]             =[ 2( -271.1 kJ) ] - [ 0 + 0 ]             ˜-543.2 kJ So the answer is (b) Substitute the value of Hf (HF) from the data in yourbook to get the exact value.

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