Calculate Grxn at 315 K under the non-standardconditions for the following react

Question

Calculate Grxn at 315 K under the non-standardconditions for the following reaction: 2 Hg(g)+O2(g) 2HgO(s)         G0= - 180.8 kJ PHg= 0.025atm,  PO2=0.037atm I know I use this equation: G= G0- RTln Q Q = [products]/[reactant] but in thisproblem the product is in a different phase (solid) so I am notsure how I solve for Q. Any help would be greatlyappreciated. Calculate Grxn at 315 K under the non-standardconditions for the following reaction: 2 Hg(g)+O2(g) 2HgO(s)         G0= - 180.8 kJ PHg= 0.025atm,  PO2=0.037atm I know I use this equation: G= G0- RTln Q Q = [products]/[reactant] but in thisproblem the product is in a different phase (solid) so I am notsure how I solve for Q. Any help would be greatlyappreciated.

Explanation / Answer

Formula:             G= G0 - RTln Q Data:            G0 = - 180.8 kJ             PHg= 0.025atm,              PO2=0.037atm            Q    = 1 / ( 0.025 ) ( 0.037 )                   = 1081             T    = 315 K             R    = 8.314 J / mol . K           G=  - 180.8 kJ - ( 8.314 J / mol . K *315 K ln ( 1081)                   =   - 180.8 kJ - 18.29 kJ                   =   - 199.09 kJ                      PO2=0.037atm            Q    = 1 / ( 0.025 ) ( 0.037 )                   = 1081             T    = 315 K             R    = 8.314 J / mol . K           G=  - 180.8 kJ - ( 8.314 J / mol . K *315 K ln ( 1081)                   =   - 180.8 kJ - 18.29 kJ                   =   - 199.09 kJ                

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