Calculate H for the reaction C4H4(g) + 2H2 (g)-----C4H8 (g),using the following

Question

Calculate H for the reaction C4H4(g) + 2H2 (g)-----C4H8 (g),using the following data: H combustion for C4H4 (g) =-2341 KJ/mol H combustion for H2 (g) = -286KJ/mol H combustion for C4H8 (g) = -2755 KJ/mol please show the formula,and how to solve thanks Calculate H for the reaction C4H4(g) + 2H2 (g)-----C4H8 (g),using the following data: H combustion for C4H4 (g) =-2341 KJ/mol H combustion for H2 (g) = -286KJ/mol H combustion for C4H8 (g) = -2755 KJ/mol please show the formula,and how to solve thanks

Explanation / Answer

combustion for C4H4 C4H4 + 5)2 ----> 4 CO2 + 2 H2O   :H1 = -2341 KJ / mol   ----- ( 1) combustion for H2 2 H2 + O2 ------> 2 H2O : H2 = -286 KJ /mol    ----- ( 2 ) combustion for C4H8 C4H8 + 6 O2 ----> 4 CO2 + 4 H2O : H3 =-2755 KJ / mol   ----- ( 3 ) C4H4(g) + 2H2 (g)-----C4H8 (g)   : H =?-----(4) Eq ( 4 ) can be obtained by Eq(1) + Eq ( 2 ) + reverse of Eq (3 ) So, H = H 1 + H 2 + ( - H 3 )            = -2341 + ( -286 ) + ( - ( -2755 ) )            = 128 KJ / mol

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