Calculate H for the reaction below using Hess\'Law. 2C 2 H 6 (g)-->2C 2 H 2 (g)+

Question

Calculate H for the reaction below using Hess'Law. 2C2H6(g)-->2C2H2(g)+4H2(g)            H=? C2H2(g)+5/2O2(g)--->2CO2(g)+H2O(l)         H=-1300kJ 2H2(g)+O2(g)-->2H2O(l)                                H=-572kJ 2C2H6(g)+7O2(g)-->4CO2(g)+6H2O(l)          H=-3120kJ Calculate H for the reaction below using Hess'Law. 2C2H6(g)-->2C2H2(g)+4H2(g)            H=? C2H2(g)+5/2O2(g)--->2CO2(g)+H2O(l)         H=-1300kJ 2H2(g)+O2(g)-->2H2O(l)                                H=-572kJ 2C2H6(g)+7O2(g)-->4CO2(g)+6H2O(l)          H=-3120kJ

Explanation / Answer

We Know that :      According to Hess's Law we candetermine the enthalpy of the reaction.      2C2H6(g)-->2C2H2(g)+4H2(g)      H =     The given equations are :           C2H2(g)+5/2O2(g)--->2CO2(g)+H2O(l)         H=-1300kJ ---- 1    2H2(g)+O2(g)-->2H2O(l)                                H=-572kJ ----   2    2C2H6(g)+7O2(g)-->4CO2(g)+6H2O(l)          H=-3120kJ ----- 3       H =    (3) - [2 x (1) + 2 x (2) ]                = -3120 kJ - [ 2 x (-1300) + 2 x (-572) ]kJ                  = + 624 kJ
   C2H2(g)+5/2O2(g)--->2CO2(g)+H2O(l)         H=-1300kJ ---- 1    2H2(g)+O2(g)-->2H2O(l)                                H=-572kJ ----   2    2C2H6(g)+7O2(g)-->4CO2(g)+6H2O(l)          H=-3120kJ ----- 3       H =    (3) - [2 x (1) + 2 x (2) ]                = -3120 kJ - [ 2 x (-1300) + 2 x (-572) ]kJ                  = + 624 kJ

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