What is the reducing agent in the reaction below? Cr 2 O 7 2- +6S 2 O 3 2- + 14H

Question

What is the reducing agent in the reaction below? Cr2O72- +6S2O32- + 14H+ =2Cr3+ + 3S4O62- +7H2O a)Cr2O72-          b)S2O32- c)H+ d)Cr3+ e)S4O62- f)H2O g)none of these; this is not a redox reaction I am having trouble deciding which one is losingelectrons/being oxidized. What is the reducing agent in the reaction below? Cr2O72- +6S2O32- + 14H+ =2Cr3+ + 3S4O62- +7H2O a)Cr2O72-          b)S2O32- c)H+ d)Cr3+ e)S4O62- f)H2O g)none of these; this is not a redox reaction I am having trouble deciding which one is losingelectrons/being oxidized. f)H2O g)none of these; this is not a redox reaction I am having trouble deciding which one is losingelectrons/being oxidized.

Explanation / Answer

S2O32-    is the reducing agent the oxidation number of Cr in Cr2O72-         ion is +6 , that is reduced to +3 by S2O32-ion.so,it   is the reducingagent S2O32-ion.so,it   is the reducingagent

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