As you can see, I can\'t seem to figure out step 3. This iswhat I did so far: I

Question

As you can see, I can't seem to figure out step 3. This iswhat I did so far: I calculated the moles of HNO3 left over whichgave me 0.04512 moles, which is also 0.04512 moles NaOH. I usedthat # to figure out how many L of NaOH to titrate the acid, whichis 0.01128L, now I'm stuck. What do I do to figure out the volumefor Cu(OH)2?

Explanation / Answer

You said only post hints, why somewhat helpful? Anyway, here my answer: Cu            + 4HNO3--> Cu(NO3)2 +2NO2+2H2O 8.73*10-3                -->8.73*10-3      Cu(NO3)2+ 2NaOH-->Cu(OH)2+ 2NaNO3 8.73*10-3 -->0.01746mol The total mole of NaOH: 0.01746+0.04512=0.06258(mol) The Volume of NaOH:0.06258/4=0.015645L=15.645mL

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